# convex lens formula class 10

The image is real, inverted and enlarged in size. should be placed at a distance of 54 cm on the object side of the mirror to obtain a sharp image. We draw the ray diagram as follows:(i) Draw the principal axis (a horizontal line). This lens diverges a straight beam of light. If this equation shows a negative focal length, then the lens is a diverging lens rather than the converging lens. (v) Draw a line AD parallel to principal axis and then, allow it to pass straight through the focus (F') on the right side of the lens. We are given a convex mirror. (iii) Mark points F and B on the left side of lens at a distance of 3 cm and 2 cm respectively. Now, we draw the ray diagram as follows:(i) Draw a horizontal line to represent the principal axis of the convex lens. (iv) Draw an arrow AB of height 1 cm on the left side of lens at a distance of 5 cm from the lens. The major differences between concave and convex lens two are: These are used for a variety of purposes in our day-to-day lives. (vii) Draw a line CA', backwards, so that it meets the line from D parallel to principal axis at A. Here, Object size, h = + 7.0 cmObject distance, u = - 27 cmFocal length, f = - 18 cm Image distance, v = ? View Answer NCERT Question 9 - One-half of a convex lens is covered with a black paper. This lens is thicker at the centre and gets thinner as we move towards the edges. (vi) Draw a line A'B', perpendicular to principal axis from B'. Magnification, m = -vu= h'h Therefore,  Image size, h' = -vhu                          = -8.6 × 5-20                         = 2.15 ≃ 2.2 cm. Example 10.4 - A 2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. converges the incident rays towards the principal axis) which is relatively thick across the middle and thin at the lower and upper edges. Class 1 - 3; Class 4 - 5; Class 6 - 10; Class 11 - 12; CBSE. (x) Then, measure CB' and A'B'. Second Formula for Magnification There is another formula of magnification Note : - If magnification (m) is positive , It means image formed is virtual and erect If magnification (m) is negative, It means image formed is real and inverted Questions Example 10.1 - A convex mirror used for rear-view on an automobile has a radius of curvature of 3.00 m. This formula is applicable to both convex and concave lenses. This lens formula is applicable to both the concave and convex lens. This lens converges a straight beam of light. However, if one of the surfaces is flat and the other convex, then it is called a plano-convex lens. Draw the ray diagram and find the position, size and the nature of the image formed. 232, Block C-3, Janakpuri, New Delhi, (ix) Now AB', represents the real, but inverted image of the object AB. (xi) Thus the final position, nature and size of the image A'B' are:         (a) Position of image A'B' = 3.3 cm × 5 = 16.5 cm from the lens on opposite side. (viii) Draw AB', perpendicular to the principal axis from A'. There is another type of lens known as concave lens. Drawing the ray diagram: Using a scale of 1: 5, we get v = - 2 cm, f = - 3 cm. (v) Draw a line AD, parallel to principal axis. At what distance from the mirror should a screen be placed so that a sharp focussed image can be obtained? Here, we have Object size, h = + 5 cm Object distance, u = -20 cmRadius of curvature, R = + 3.0 cm [R is +ve for a convex mirror]∴ Focal length ,  f = R2 = +15 cm From mirror formula,                      1v = 1f-1u we have,                       1v= 1+15-1-20      = 4+360     = 760 Image distance, v = 607≃ 8.6 cm. (ii) Draw a convex lens, keeping principal centre (C) on the principal axis. Is the same formula applicable to both convex and concave lenses? 2020 Zigya Technology Labs Pvt. Draw the ray diagram. BOOK FREE CLASS ; COMPETITIVE EXAMS. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. (vi) Draw a line from A to C (centre of the lens), which goes straight without deviation. It will be found to be equal to 6 cm.Thus, object is placed at a distance of 6 cm × 5 = 30 cm from the lens. (iv) Join any point D (nearly at the top of lens) and F by a dotted line. It is found that CB' = 3.3 cm and A'B' = 0.7 cm. Find the nature, position and size of the image. Though we derived it for a real image formed by a convex lens, the formula is valid for both convex as well as concave lenses and for both real and virtual images. Ans. cool website Hi I am Girish Chandra.Welcome to my youtube channel Chandra Mathematics. Magnification, m = h'h = -vu ∴ Image size,                         h' = -vhu                              =-(-54)×(+7)(-27)= -14 cm The image is real, inverted and enlarged in size. So the most common use of the lens is that it helps us to see. Focal length, f = - 15 cm    [f is - ve for a concave lens]Image distance, v = - 10 cm [Concave lens forms virtual image on same side as the object, so v is - ve]As,                                                          Object distance, u = -30 cm. Now, using the mirror formula,                      1u+1v = 1f∴                  1v = 1f-1u ⇒                      = 1-18-1-27 = -3+254 = -154i.e.,                  v = -54 cm The screen should be placed at a distance of 54 cm on the object side of the mirror to obtain a sharp image. How far is the object placed from the lens? A simple kind of these lenses can focus light into an image, but that image won’t be of a high quality. It is used to correct Hypermetropia or long-sightedness. For example. Focal length, f = - 15 cm    [f is - ve for a concave lens], Image distance, v = - 10 cm [Concave lens forms virtual image on same side as the object, so v is - ve]. 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